PK 5kQBH mimetypetext/x-wxmathmlPK 5kQQdBV5 5
format.txt
This file contains a wxMaxima session in the .wxmx format.
.wxmx files are .xml-based files contained in a .zip container like .odt
or .docx files. After changing their name to end in .zip the .xml and
eventual bitmap files inside them can be extracted using any .zip file
viewer.
The reason why part of a .wxmx file still might still seem to make sense in a
ordinary text viewer is that the text portion of .wxmx by default
isn't compressed: The text is typically small and compressing it would
mean that changing a single character would (with a high probability) change
big parts of the whole contents of the compressed .zip archive.
Even if version control tools like git and svn that remember all changes
that were ever made to a file can handle binary files compression would
make the changed part of the file bigger and therefore seriously reduce
the efficiency of version control
wxMaxima can be downloaded from https://github.com/wxMaxima-developers/wxmaxima.
It also is part of the windows installer for maxima
(https://wxmaxima-developers.github.io/wxmaxima/).
If a .wxmx file is broken but the content.xml portion of the file can still be
viewed using an text editor just save the xml's text as "content.xml"
and try to open it using a recent version of wxMaxima.
If it is valid XML (the XML header is intact, all opened tags are closed again,
the text is saved with the text encoding "UTF8 without BOM" and the few
special characters XML requires this for are properly escaped)
chances are high that wxMaxima will be able to recover all code and text
from the XML file.
PK 5kQC)? )? content.xml
G376-386 - Examen parcial04 Dic 2020kill(all);f(x):=1/log(x^2+1)-1/x^2;Se comprueba que el dominio de la función es todo R menos cero, punto en el cual la función no está definida.Estudiamos los límites laterales de la función en 0. Hacerlo manualmente, requiere transformar previamente la función pra obtener una indeterminación del tipo [0/0], que permita aplicar L'Hopital. Dado que x siempre está elevada al cuadrado dentro de la expresión, los límites laterales deben coincidir, independientemente de si su valor es finito o no.Lizq:limit(f(x),x,0,minus);Lder:limit(f(x),x,0,plus);Los límites laterales coincidenis(Lizq=Lder);Por lo tanto, el valor del límite es 1/2:limit(f(x),x,0);Por lo tanto, se trata de una DISCONTINUIDAD EVITABLE. En este caso, se evita dando el valor de 1/2 a la función en x=0:f2(x):= (if x=0 then f2(x):=(1/2) else f2(x)=f(x));wxplot2d(f(x),[x,-10,10],[y,0.2,0.52]);f(x):=4*x/(x^2+3*x+2);sol:integrate(f(x),x);kill(all);g(x):=cos(x)/(1+cos(x));sol:integrate(g(x),x);kill(all);f(x):= if x<5 then x^2-2*x*abs(x-3) else x*sqrt(x^2+2) ;load(draw);wxdraw2d(explicit(f(x),x,-3,6), yrange=[-5,40], grid = true, color=red, point_type = filled_circle, point_size=2, points([[3,f(3)],[5,f(5+0.01)]]));La función es continua en x=3. Maxima no puede calcular límites de funciones definidas a trozos, y es necesario reescribir la rama de dicha función que estamos estudiando ahora:f1(x):=x^2-2*x*abs(x-3);limit(f1(x),x,3,minus);limit(f1(x),x,3,plus);Pero no derivable:cociente_diferencial:(f1(x)-f(3))/(x-3);limit(cociente_diferencial, x, 3, minus);limit(cociente_diferencial, x, 3, plus);Las derivadas laterales no coinciden, y por lo tanto la función no es derivable en x=3define(fprima(x), diff(f1(x),x));Arroja un error:fprima(3);La función no es continua en x=5 (por lo tanto tampoco derivable):f2(x):=x*sqrt(x^2+2);limit(f1(x),x,5,minus);limit(f2(x),x,5,plus);Se trata de una discontinuidad de salto finito. Por lo tanto, f(x) es derivable en todo R menos en x=3 y x=5Por lo tanto, en el intervalo [0,2] f(x) es continua, y derivable en (0,2). Además:is(f(0)=f(2));f(1)=f(2), y por lo tanto ha de existir un punto c ∈ (0,2) tal que f'(c)=0.Indicamos a maxima que estamos en la rama de la función por la izquierda de 3:assume(x<3);solve(diff(f1(x),x) = 0, x);Y encontramos que c=1kill(all);f(x):=1/x;t4:taylor(f(x),x,1,4);load(draw);wxdraw2d(key = "f(x)", explicit(f(x), x, 0,3), color = "red", key = "Taylor orden 4", explicit(t4,x,0,3), yrange=[0,8], grid = true, key =false, point_type=filled_circle, color="green", point_size = 2, points([[1,f(1)]]));Utilizando el término general de la serie:a[n]:=(-1)^n*(x-1)^n;t4n:sum(a[n],n,0,4);PK 5kQѷUrA A
image1.pngPNG
IHDR X W bKGD IDATx{@gq*ʴCbFdL#\F36Zھ_f
e1\2ؾ&(.s>_9~-z=Rt """XHXHXHXHXHXHXHXHXHXHXHXHXHXH*<ժU{DD!ķ瓐4i@2
_e(!!!!.:i@2UEy$$PNAAAѢS=J6S|C6FHXHXDjjDBHd&bbbDG R$aJHDD!!!
HTTӽ5slllΝkQĜ9sL8Q~Pt:{@@?رc͚5+ƍWƦKD$L{q
+++ C[ٳ.S~:ٍ?7|ߩDDT˥3gθTA iiiE|+WBCCCBB6o,")Qydd 4<9H-FsN5jjO4dȐ1c̟?Y<,""xɉ,=h
>-T,""¢ѡN-PhZeUVg֦!r:wF~}Ν5|":UDDѡN--==]<}t͋.u-Z<{lӦMM~s^?bzDEGj)ṹ7n,ttI YYY:.99y&LIBB0bxͺui>E4j)qqq)))u5jTTTTɓ/_N:qqq111,d7_voSw#RٟjË/χi#3B"s
K |jTX}ߘ>):nƎ&Dd,D
a{;>#n[Z1k)n%$n2o:aD%Ф vc@6gDJr$._FޥZ
XșNB-!nȌn2<-"&m&=Ya߬_#&ƸH1lK/QmL 87ѓ~*!O\1|x>u.q,y(L6gDp&зo?hm^FDdXaz<:цDd.XajxC}Q|D'[ Ov66ի.yM`$"*L)@l,w/з/6m2\ "3BH +oo;L"2#,Ds{G,Vtbг'n5d0"BH$k5X@@Ջ1d)!o6a؊''
`ggXD#3B"#>}`U X9a!$ѣ[
fm=z`vìlI-6>C}!"? !ԶmëjR֨#MEdNXuΟ!ٻ7bc
B"c!$W|